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List with users, that are subscribed to an acymailing list

  • kommid
  • kommid
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1 day 2 hours ago - 22 hours 36 minutes ago #339652 by kommid
...seems, this doesn't work either, because now CB complains about the subquery returning more than one value:
Code:
SELECT id FROM #__acym_user WHERE id IN ( SELECT id from #__acym_user_has_list WHERE list_id = 1 AND status = 1 );
This quey worked well in PHPMyAdmin....
Last edit: 22 hours 36 minutes ago by kommid.

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  • krileon
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21 hours 54 minutes ago #339654 by krileon
I am not the developer of AcyMailing. I cannot help you with AcyMailing queries. You should consult with them regarding this. This is a standard EXISTS subquery and it absolutely supports joins. Below is an example based off your earlier post, but again I'm not familiar with AcyMailing data structure so I've no clue if this is correct or not.
Code:
EXISTS( SELECT 1 FROM `#__acym_user_has_list` AS acy INNER JOIN `acym_user` acyu ON acyu.`id` = acy.`user_id` WHERE acy.`list_id` = 1 AND acy.`status` = 1 AND acyu.`user_id` = u.`id` )

Querying directly in phpmyadmin is not the same as adding an AND statement to an existing query. The developers of AcyMailing can probably suggest a more accurate and performant query based off their data structure.


Kyle (Krileon)
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  • kommid
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4 hours 51 minutes ago #339664 by kommid
Hi Kyle,
I think I might have misunderstood you at www.joomlapolis.com/forum/professional-members-support/247129-list-with-users-that-are-subscribed-to-an-acymailing-list?start=0#339604 where you say, I couldn't use joins here. After changing your query just a little bit, it now works - with a join....
Thank you so much, I really appreciate your support and you patience here

For everyone, who might have the same or a similar problem in the future, here is the working sql - at least, it worked for me:
Code:
EXISTS( SELECT 1 FROM `#__acym_user_has_list` AS haslist INNER JOIN `#__acym_user` acyuser ON acyuser.`id` = haslist.`user_id` WHERE haslist.`list_id` = 1 AND haslist.`status` = 1 AND acyuser.`cms_id` = u.`id` )

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